Jet Roadster

Best time—

Your 2000 kg roadster carries 90 kg of compressed air and nothing else to push it. The straight A→B (45 m) is frictionless ice; the quarter-circle B→C (radius 20 m) has grip, μ = 0.1. The tail jet gives 20 kN and burns 40 kg/s. The side jet blows outward, so it pushes the car toward the centre O; it burns 2 kg/s for every kN. Get to C as fast as you can without skidding.

Controls · hold ↑ tail jet · hold ← or Q side jet · [ ] side power · Space pause · R restart · V camera

Drive the same car anywhere on the field. Now it has steering and brakes, which both work by friction: the tyres can push the car with at most μN in any direction. Find out what happens on the ice (the straight and the round rink), try the 20 m circle, the slalom, and the side jets on both surfaces.

Controls · ↑ tail jet · ↓ brake · ← → steer · Q E side jets · [ ] side power · R back to start · V camera

Ready
0.00 s
Hold ↑ to fire the tail jet · Hold ← for the side jet↑ jet · ↓ brake · ← → steer · Q E side jets
0.0m/s
Speed
TAIL SIDE BRAKE SKID
Air reserve90.0 kg
Flow0.0 kg/s
Grip
Physics model, the ideal plan and free drive +

1 · Thrust on the ice

Air leaves the nozzle at u = 500 m/s. The thrust is the momentum carried away per second:

F=uΔmΔt=500×40=20 kN,a=Fm=10 m/s2

Ice has no friction, so once the jet stops the car keeps its speed. The fastest straight is: burn first, then coast. Reaching speed v costs

qAB=mvu=4v(kg)

A side jet on the ice gives a sideways velocity that nothing can remove. You either slide off the ice or reach B already skidding.

2 · Holding the curve

To stay on the arc the car needs a net force toward O. Friction can supply up to μN, with N = mg + Ffan; the side jet supplies S:

mv2R=f+S,|f|≤μN

While the tyres roll this is static friction, and it takes whatever value is needed. So the side thrust must stay inside a window:

mv2R−μN≤S≤mv2R+μN

Too little and the car slides outward; too much and it is pushed in toward O. Either way the tyres slide, friction becomes kinetic (μN, against the sliding), and the car can no longer be steered round the arc.

3 · The ideal plan

Use the least side thrust, S = mv2/R − μN, for the time t = πR/(2v). The air left after the straight must last the curve:

4v+(mv2R−μN)u·πR2v=90

With the fan on and the textbook value π = 3 this gives 10v−360v=90, so v = 12 m/s: 48 kg on the straight and 42 kg in the curve, 6.85 s in total. Entering any faster leaves too little air for the curve.

The game draws a true circle (π = 3.14159…), so its ideal plan is slightly slower.

4 · Free drive: steering is friction

The tyres can push the car in any horizontal direction, but never harder than μN in total (the friction circle). Turning the wheels by an angle δ asks the car to follow a circle of radius

r=Ltan⁡δ,mv2r≤μN

with wheelbase L = 4 m. Within the limit the friction is static and the car rolls round the circle. Beyond it the tyres slide, friction becomes kinetic (μN against the slide) and the car runs wide. Brakes use friction too: they take 70 % of μN, so braking hard in a turn leaves little for steering.

On ice μ = 0: steering and brakes have nothing to push against. Only the jets can change the velocity, and the car keeps sliding in a straight line whichever way it points.

Model assumptions

  • Mass stays 2000 kg (the 90 kg of air lost is ignored); no air drag or rolling resistance; nozzle exit pressure equals the outside pressure, so F = u·Δm/Δt.
  • The car is treated as a point. The tail jet pushes along the lane; the side jet pushes straight toward O on the curve (toward the inner edge on the ice). Tyres roll freely along the lane, so friction acts only across it.
  • Skidding means the tyres slide across the lane: friction is then kinetic, μN, opposite the sliding, and the run is lost. Beyond the road edge the run-off area is treated as frictionless. This is a classroom illustration, not a prediction of how a real car spins.
  • The centripetal force is the net force toward O, not an extra force. The dashed line shows its direction; blue arrows are jet thrust, amber arrows friction, all at 1 m per 2.5 kN. The car is drawn 1.35× larger and the air jets are slowed down so they can be seen.

Background: NASA · thrust equation ↗ OpenStax · centripetal force and static friction ↗

Textbook check (π = 3)
PlanSpeed at BAir on straightAir in curveTime
10 m/s, fan on10 m/s40 kg24 kg8 s
10 m/s, fan off10 m/s40 kg48 kg8 s
Ideal, fan on12 m/s48 kg42 kg6.85 s
All air on the straight22.5 m/s90 kgnone leftskids at B